sql-server-2005 – 如何为逗号分隔的代码字符串获取相应的逗号

我有一个表,有一个名为“locations”的列,其类型为varchar(max).它带有逗号分隔的代码串,例如’1,3,4′.另一方面,我有一张表将这些代码映射到某些位置,例如

1 -- British
2 -- New Zealand
3 -- Hong Kong
4 -- Taiwan

我的问题是,我正在制作一个VIEW,它将列“位置”的内容映射并替换为相应的逗号分隔文本,例如： ‘1,4’将是’英国,香港,台湾’

这对公司项目来说真的很紧迫,敬请劝告.

谢谢！

问候,
威廉

解决方法

表结构

create table Locations(LocationID int,Location varchar(50))
create table OtherTable(ID int,Locations varchar(max))

测试数据

insert into Locations values(1,'Location <1>')
insert into Locations values(2,'Location <2>')
insert into Locations values(3,'Location <3>')
insert into Locations values(4,'Location <4>')
insert into Locations values(5,'Location <5>')

insert into OtherTable values (1,'')
insert into OtherTable values (2,'2')
insert into OtherTable values (3,'1,5')

询问

;with cte as
(
  select 
    T.ID,coalesce(L.Location,'') as Location
  from OtherTable as T
    cross apply
      (select cast('<r>'+replace(T.Locations,','</r><r>')+'</r>' as xml)) LocXML(XMLCol)
    cross apply
      LocXML.XMLCol.nodes('r') LocID(IDCol) 
    left outer join Locations as L
      on L.LocationID = LocID.IDCol.value('.','int')
)
select
  C1.ID,stuff((select ','+C2.Location
         from cte as C2 
         where C1.ID = C2.ID
         for xml path(''),type).value('text()[1]','nvarchar(max)'),1,2,'') as Locations
from cte as C1
group by C1.ID

结果

ID  Locations
--- ----------------------------------------
1   
2   Location <2>
3   Location <1>,Location <3>,Location <5>

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