加入收藏 | 设为首页 | 会员中心 | 我要投稿 济南站长网 (https://www.0531zz.com/)- 科技、建站、经验、云计算、5G、大数据,站长网!
当前位置: 首页 > 教程 > 正文

Oracle case函数使用详解

发布时间:2021-11-28 19:24:00 所属栏目:教程 来源:互联网
导读:1.创建测试表: 复制代码 代码如下: DROP SEQUENCE student_sequence; CREATE SEQUENCE student_sequence START WITH 10000 INCREMENT BY 1; DROP TABLE students; CREATE TABLE students ( id NUMBER(5) PRIMARY KEY, first_name VARCHAR2(20), last_name VA

1.创建测试表:
 
复制代码 代码如下:
 
 
DROP SEQUENCE student_sequence;
CREATE SEQUENCE student_sequence  START WITH 10000  INCREMENT BY 1;
 
DROP TABLE students;
CREATE TABLE students (
  id               NUMBER(5) PRIMARY KEY,
  first_name       VARCHAR2(20),
  last_name        VARCHAR2(20),
  major            VARCHAR2(30),
  current_credits  NUMBER(3),
  grade     varchar2(2));
 
INSERT INTO students (id, first_name, last_name, major, current_credits,grade)
  VALUES (student_sequence.NEXTVAL, 'Scott', 'Smith', 'Computer Science', 98,null);
 
INSERT INTO students (id, first_name, last_name, major, current_credits,grade)
  VALUES (student_sequence.NEXTVAL, 'Margaret', 'Mason', 'History', 88,null);
 
INSERT INTO students (id, first_name, last_name, major, current_credits,grade)
  VALUES (student_sequence.NEXTVAL, 'Joanne', 'Junebug', 'Computer Science', 75,null);
 
INSERT INTO students (id, first_name, last_name, major, current_credits,grade)
  VALUES (student_sequence.NEXTVAL, 'Manish', 'Murgratroid', 'Economics', 66,null);
 
commit;
 
2.查看相应数据
 
复制代码 代码如下:
 
 
SQL> select * from students;
 
        ID FIRST_NAME           LAST_NAME            MAJOR                          CURRENT_CREDITS GR
---------- -------------------- -------------------- ------------------------------ --------------- --
     10000 Scott                Smith                Computer Science                            98
     10001 Margaret             Mason                History                                     88
     10002 Joanne               Junebug              Computer Science                            75
     10003 Manish               Murgratroid          Economics                                   66
 
3.更新语句
 
复制代码 代码如下:
 
 
update students
set grade = (
select grade from
(
select id,
case when current_credits > 90 then 'a'
     when current_credits > 80 then 'b'
     when current_credits > 70 then 'c'
else 'd' end grade
from students
) a
where a.id = students.id
)
/
 
4.更新后结果
 
复制代码 代码如下:
 
 
SQL> select * from students;
 
        ID FIRST_NAME           LAST_NAME            MAJOR                          CURRENT_CREDITS GR
---------- -------------------- -------------------- ------------------------------ --------------- --
     10000 Scott                Smith                Computer Science                            98 a
     10001 Margaret             Mason                History                                     88 b
     10002 Joanne               Junebug              Computer Science                            75 c
     10003 Manish               Murgratroid          Economics                                   66 d

(编辑:济南站长网)

【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容!

    热点阅读